I was learning about right shift operator in one of the corey's links

http://radio.javaranch.com/channel/corey/changeCategory.action?category=languageFundamentals Right shifting the positive number is ok,but with negative number,

I had a doubt.Let me interpret what I have understood.

With respect to the most significant number in the right side of the binary number to be shifted,if it is 0 then the number is positive and we put 0's from the left,and if it is 1 then the number is negative,and we put 1's from the left.So let's say...

-13>>=1

To represent 13 as negative ,we use 2's complement...

00000000 00000000 00000000 00001101 (The value of 13)

11111111 11111111 11111111 11110010 (We flip 0's to 1's and 1's to 0's)

00000000 00000000 00000000 00000001 (We add the value of 1 )

11111111 11111111 11111111 11110011 (This result represents -13)

Now as -13(binary form) has 1 in its sign bit,therfore when shifting this binary number to the right we add 1 from the left.Right!!

This turns up to

11111111 11111111 11111111 11111001 ( The result)

To evaluate this,we do it as

-2(pow of 31) + 2(pow of 30) .....+2(pow of 3)+2(pow of 0) (I wanted to verify is this the way we need to evaluate the number ?).

If yes, then the answer has to be -7.

But I'am not getting my answer right.

I have -2(pow of 31) as -2147483648 and by adding numbers from

2(pow of 30) to 2(pow of 3) and 2(pow of 0) I get 2147483644.

So,(-2147483648+2147483644) gives me -4 rather than -7,why? am I missing something here.

Please help.