Can someone fix me?

[Carl Headley]

Below is my code. What I've been trying to do for the past six days is design a loop that reads five integers, sorts them using a while loop, and print out the smallest number entered. I can easily accomplish this with the for loop, but have no clue as to how this is done using a while loop. Can someoone please fix me?



import java.text.*; //this package supports number formatting class
import java.util.Arrays; //this package supports Arrays


public class Whileloop
{
public static void main(String[] args)
{

int[] number = new int[5];

int index=0;
int sum;
System.out.println("Enter 5 whole numbers: ");

sum = 0;
do
{

number [index] = SavitchIn.readLineInt( );
index=index+1;
sum=sum+1;
}while (sum < 5);
/*This part sorts*/

while (number[0]<number[1]&&number[2]&&number[3]&&number[4]);
{

do{
if (number[0]!<number[1]&&number[2]&&number[3]&&number[4])
System.out.print("searching.");
else {System.out.print("the smallest number is"+number[0]);}
} while (number[1]<number[0]&&number[2]&&number[3]&&number[4]);

do{if (number[1]!<number[0]&&number[2]&&number[3]&&number[4]);
System.out.print("...");
else System.out.print("the smallest number is"+number[1]);
} while (number[2]<number[0]&&number[1]&&number[3]&&number[4]);

do{if (number[2]!<number[1]&&number[0]&&number[3]&&number[4]);
System.out.print("...");
else System.out.print("the smallest number is"+number[2]);

} while (number[3]<number[0]&&number[1]&&number[2]&&number[4]);

do{if (number[3]!<number[1]&&number[2]&&number[0]&&number[4]);
System.out.print("...");
else System.out.print("the smallest number is"+number[3]);

} while (number[4]<number[0]&&number[1]&&number[3]&&number[2]);

do{if (number[4]!<number[1]&&number[2]&&number[3]&&number[0]);
System.out.print("...");
else System.out.print("the smallest number is"+number[4]);


}
System.out.print(/n"Thank"+number[0]);


}}


Any corners that can be cut in the while loops would be greatly appreciated.

[Michael Dunn]

I can easily accomplish this with the for loop, but have no clue as to how this is done using a while loop.

They're basically the same

for(int x = 0; x < 10 ; x++)
{
//do something
}

int x = 0;
while(x < 10)
{
//do something
x++
}

[Lisa D'Aniello]

Hi Carl,

Holy while loops! To cut down on the loops, you could use 2 loops instead of 5.

You will need 2 temporary variables, 2 counters. Here is the example from my textbook that helped me a lot when I was first learning C++ (slightly modified to fit java syntax)

while(index < 5)
//loop through each index in your initial array
{
  temp1 = number[index];
  //store your current array value into a temp var
 
  i = 0;
  //set an int variable to zero for your nested loop
 
  while(i < 5)
  //now you need to loop again for the actual comparison
  {
    if(temp1 <= number[i])
    //if your temporary variable is less than the current value
    {
      temp2 = number[i];
      //store the current value into another temp variable
 
      number[i] = temp1;
      //add the first temp value to the current array slot
 
      number[index] = temp2;
      //then replace the initial comparison index with the 2nd temp value
    }
    i++;
  }
  index++;
}

[Carl Headley]

thanks for the quick response, but could you explain how I could swap the numbers for the sort?

[Carl Headley]

thanks so so much everybody.

[Dirk Schreckmann]

When posting code, please be sure to surround the code with the [code] and [/code] UBB Tags. This will help to preserve the formatting of the code, thus making it easier to read and understand.