And how do I do this?

[Manuel Diaz]

OK, I want to make a program that read a text input by the user. For example, I need this letters for the program (h,e,l,p), I want the program that convert those letters into numbers, I have this code:

  if (letter == 'h' || letter == 'H')
            number = 0;
        if (letter == 'e' || letter == 'E')
            number = 1;
        if (letter == 'l' || letter == 'L')
            number = 2;
        if (letter == 'p' || letter == 'P')
            number = 3;

OK, that's fine, but it seems odd to me. Can I make an array to check the letters, like this:

array = {h,e,l,p};
number = {0,1,2,3};

If the user inputs one of those letters, the program finds on the array of numbers, the number that correspond with that letter. Can someone help me??

THANKS IN ADVANCE.

[M Beck]

the word "help" has no repeated letters — that is, every letter in it occurs only once in it. so long as that remains true (so long as you don't switch to some other word that does have repeated letters) the String.indexOf() method might prove useful.

[Manuel Diaz]

Can you please be more specific?

Supose that the user inputs: h89

I split the word and then how can I use String.indexOf() to say that the 'h' has to become and '0' for example?

[Manuel Diaz]

OK,I finally found that part. But what about if I want it in the inverse?. The user inputs a number: 1

Then the program has to check in the variable number "12345678". Now I want to convert that 1 the user inputs into a, 2 into b, 3 into c. Any suggestions?

[M Beck]

well, if you've figured out how to use .indexOf() to go from 'e' to 2 in the word "help" (or actually i think you'll be going from 'e' to 1, since the indexes that indexOf() returns are zero-based; just add 1 to fix that), then going back is equally easy. you'll want to read about the String.charAt() method, and keep in mind you'll have to convert the indexes to being zero-based first; that just means subtracting 1.