posted 12 years ago
Java integers can have three representations, base8 (octal), base10, and base16 (hexadecimal)?
I am guessing this is short, int, and long. Am I close ?
I am guessing this is short, int, and long. Am I close ?
posted 12 years ago
It's a good guess, but you're mixing two different concepts.
Ultimately, everything is stored as bits (zeros and ones). In Java, byte, short, int, and long are primitive types for storing integral values. These types are distinguished by the number of bits they can hold (8, 16, 32, and 64 respectively).
Different base representations (decimal, octal, and hexadecimal) are available to the Java programmer as different ways to express integral values.
Octal (base 8) literals are prefixed with zero. For example, 034 is an octal representation of 28. Hexadecimal (base 16) literals are prefixed with zero and the letter x, using letters af to represent 1015. (The letters are not case sensitive.) For example, 0x1c is a hexadecimal representation of 28.
Originally posted by Charlie James:
Java integers can have three representations, base8 (octal), base10, and base16 (hexadecimal)? I am guessing this is short, int, and long. Am I close ?
It's a good guess, but you're mixing two different concepts.
Ultimately, everything is stored as bits (zeros and ones). In Java, byte, short, int, and long are primitive types for storing integral values. These types are distinguished by the number of bits they can hold (8, 16, 32, and 64 respectively).
Different base representations (decimal, octal, and hexadecimal) are available to the Java programmer as different ways to express integral values.
Octal (base 8) literals are prefixed with zero. For example, 034 is an octal representation of 28. Hexadecimal (base 16) literals are prefixed with zero and the letter x, using letters af to represent 1015. (The letters are not case sensitive.) For example, 0x1c is a hexadecimal representation of 28.
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Charlie James
Greenhorn
Posts: 3
posted 12 years ago
It might also help to visualize this...
As I mentioned, the primitive integral types are distinguished by the number of bits they can hold. This is what is implied by "widening" and "narrowing" type conversions. But whether you enter a value as 28, 034, or 0x1c (decimal, octal, or hexidecimal), it's stored as bits...
byte (8 bits):
00011100
short (16 bits):
0000000000011100
int (32 bits):
00000000000000000000000000011100
long (64 bits):
0000000000000000000000000000000000000000000000000000000000011100
As I mentioned, the primitive integral types are distinguished by the number of bits they can hold. This is what is implied by "widening" and "narrowing" type conversions. But whether you enter a value as 28, 034, or 0x1c (decimal, octal, or hexidecimal), it's stored as bits...
byte (8 bits):
00011100
short (16 bits):
0000000000011100
int (32 bits):
00000000000000000000000000011100
long (64 bits):
0000000000000000000000000000000000000000000000000000000000011100
"We're kind of on the level of crossword puzzle writers... And no one ever goes to them and gives them an award." ~Joe Strummer
sscce.org
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