• Post Reply Bookmark Topic Watch Topic
  • New Topic
programming forums Java Mobile Certification Databases Caching Books Engineering Micro Controllers OS Languages Paradigms IDEs Build Tools Frameworks Application Servers Open Source This Site Careers Other Pie Elite all forums
this forum made possible by our volunteer staff, including ...
Marshals:
  • Campbell Ritchie
  • Ron McLeod
  • Paul Clapham
  • Tim Cooke
  • Jeanne Boyarsky
Sheriffs:
  • Rob Spoor
  • Devaka Cooray
  • Liutauras Vilda
Saloon Keepers:
  • Stephan van Hulst
  • Tim Holloway
  • Carey Brown
  • Tim Moores
  • Mikalai Zaikin
Bartenders:
  • Piet Souris

Need help in stringObj.replaceAll()

 
Ranch Hand
Posts: 51
  • Mark post as helpful
  • send pies
    Number of slices to send:
    Optional 'thank-you' note:
  • Quote
  • Report post to moderator
This line of code giving me errors.



I just want to replace single backslash with double. How to do that in a simple way. I have wrote a custom method to do this temporarily.

Please help me out folks.
 
Java Cowboy
Posts: 16084
88
Android Scala IntelliJ IDE Spring Java
  • Mark post as helpful
  • send pies
    Number of slices to send:
    Optional 'thank-you' note:
  • Quote
  • Report post to moderator
Backslash has a special meaning in Java source code, so you have to escape it by doubling it. But backspace also has a special meaning in regular expressions, so you have to double it again. Try this:

"^(19|20)\\d{2}$".replaceAll("\\\\", "\\\\\\\\");
 
Wanderer
Posts: 18671
  • Mark post as helpful
  • send pies
    Number of slices to send:
    Optional 'thank-you' note:
  • Quote
  • Report post to moderator
If you're using JDK 5, you can use

See also a similar discussion here.
 
Babar Qadri
Ranch Hand
Posts: 51
  • Mark post as helpful
  • send pies
    Number of slices to send:
    Optional 'thank-you' note:
  • Quote
  • Report post to moderator
Thanks Jesper, its working.
Thanks Jim for a valuable information.
 
Consider Paul's rocket mass heater.
reply
    Bookmark Topic Watch Topic
  • New Topic