George Lin

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Posts: 125

vivekkumar sharma

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Posts: 70

Virag Saksena

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Posts: 71

George Lin

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Posts: 125

posted 11 years ago

Virag,

It seems very efficient! But I can not find the algorithm you mentioned from Google by searching key words "Tarjan cycle graph". Could you help to provide more information please?

regards,

George

Originally posted by Virag Saksena:

Tarjan's algorithm for detecting cycles will find cycles in O(n+e) time in a directed graph with n vertices and e edges.

It seems very efficient! But I can not find the algorithm you mentioned from Google by searching key words "Tarjan cycle graph". Could you help to provide more information please?

regards,

George

George Lin

Ranch Hand

Posts: 125

posted 11 years ago

vivekkumar,

I do made a search before I posted this question before. The issue is that, I do not know the name of the algorithm so that I can not find much useful information from Google. Could you help please? :-)

I have tried this method. I do not think this method is correct. For example, suppose in a simple graph, there are four nodes, A, B, C, D. The directed graph has the following edges,

A-->B

A-->C

B-->D

C-->D

In this graph, there is no cycle. But when running your method, since node D will be accessed twice both by node B and by node C, the directed graph will be detected cycle by your method.

Maybe I do not quite understand your method, could you provide a simple implementaion of your method please?

regards,

George

Originally posted by vivekkumar sharma:

Hi,

do bit of Google

I do made a search before I posted this question before. The issue is that, I do not know the name of the algorithm so that I can not find much useful information from Google. Could you help please? :-)

Originally posted by vivekkumar sharma:

Otherwise to detect a circle in a graph ,

keep track of nodes visited starting from a particular node,(using a set may be helpful) and if u get same node from where you started ,you have detected a circle.

I have tried this method. I do not think this method is correct. For example, suppose in a simple graph, there are four nodes, A, B, C, D. The directed graph has the following edges,

A-->B

A-->C

B-->D

C-->D

In this graph, there is no cycle. But when running your method, since node D will be accessed twice both by node B and by node C, the directed graph will be detected cycle by your method.

Maybe I do not quite understand your method, could you provide a simple implementaion of your method please?

regards,

George

Praveena Jayanthi

Greenhorn

Posts: 10

posted 11 years ago

George,

I tried to implement a sample implementation with a simple DataStructure "NodeLink" to indicate "From" and "To" vertices of a link.

Following are the steps to approach this problem

1)Make an appropriate data structure to represent the graph, its vertices and node links.

2)Construct partial graphs for each entry in the nodelinks i.e all the vertices approachable from a given vertex.

3)Iterate through the partial graphs constructed to see if any node is visited more than once in a subgraph.

In the program below, I used a hastable to keep track of nodes and the number of times visited count. I would initialize the hashtable with "0 visit counts" for each partial graph.

I hope this helps!

-Praveena

I tried to implement a sample implementation with a simple DataStructure "NodeLink" to indicate "From" and "To" vertices of a link.

Following are the steps to approach this problem

1)Make an appropriate data structure to represent the graph, its vertices and node links.

2)Construct partial graphs for each entry in the nodelinks i.e all the vertices approachable from a given vertex.

3)Iterate through the partial graphs constructed to see if any node is visited more than once in a subgraph.

In the program below, I used a hastable to keep track of nodes and the number of times visited count. I would initialize the hashtable with "0 visit counts" for each partial graph.

I hope this helps!

-Praveena

Virag Saksena

Ranch Hand

Posts: 71