Can anybody please tell me why e# is an invalid identifier?
The compiler shows # as an illegal character, but isn't # one of the unicode characters?
* The first character of an identifier must be a letter, an underscore(_), or a dollar sign($).
* The rest of the characters in the identifier can be a letter, underscore, dollar sign, or digit. Note that spaces are NOT allowed in identifiers.
* Identifiers are case-sensitive. This means that age and Age are different identifiers.
* Identifiers cannot match any of Java's reserved words.
From Java Language Specification, 3.8 Identifiers...
An identifier is an unlimited-length sequence of Java letters and Java digits, the first of which must be a Java letter...
The Java letters include uppercase and lowercase ASCII Latin letters A-Z (\u0041-\u005a), and a-z (\u0061-\u007a), and, for historical reasons, the ASCII underscore (_, or \u005f) and dollar sign ($, or \u0024). The $ character should be used only in mechanically generated source code or, rarely, to access preexisting names on legacy systems.