is this program fine?

[pras]

class Temp {

public static void main(String args[]) {

int x;
x=10;
if(x==10)
{
int y=20;

System.out.println("x is " +x);
System.out.println("y is " +y);
x=y*20;
}

System.out.println("x is" +x);

/***************************doubt****************/
IN the above line x should print 10 since x=y*20 value should be retained in the block only ,but when i run this program i get x=40 ?? can anyone tell why?
}
}

[Gavin Tranter]

Hi, the result of x=y*20; will be retained because you are assigning the result to a vairable that is in scope for the scope of the method.
If you tried to print out the value of y (in your last print statement) you would get a compilor error, as y is no longer in scope, because it has block level scope for the block it was decalred in.

[Jaime M. Tovar]

The variable scope was defined when the variable was declared, not when it was used.
[ August 31, 2007: Message edited by: Jaime Tovar ]

[Burkhard Hassel]

Howdy, the scope of int x is the whole main method. You can see it better when the code is indented:

class Temp {
 
public static void main(String args[]) {
[I]int x;
x = 10;
if (x == 10) {
int y = 20;
System.out.println("x is " + x);
System.out.println("y is " + y);
x = y * 20;
}
System.out.println("x is" + x); [/I]
}
}

scope of x in italics.



Bu.