posted 10 years ago

I'm sorry, but not a guru

double d = 2 / 3

Both 2 and 3 are integers, therefore an integer division is done which gives zero as the integer result. This result is then converted to a zero double.

double d = 2 / 3d

Here 3 is a double, therefore the 2 is converted to a double and a double division is done, which gives 0.666 as result that is assigned to the double d

(therefore for example

int i = 2 / 3 would work fine, and

int i = 2 / 3d not)

double d = 2 / 3

Both 2 and 3 are integers, therefore an integer division is done which gives zero as the integer result. This result is then converted to a zero double.

double d = 2 / 3d

Here 3 is a double, therefore the 2 is converted to a double and a double division is done, which gives 0.666 as result that is assigned to the double d

(therefore for example

int i = 2 / 3 would work fine, and

int i = 2 / 3d not)

posted 10 years ago

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