posted 10 years ago
Math.random() generates a random double between 0.0 and 1.0 (including 0.0, but not including 1.0). So multiplying this by your array's length would give you a random double between 0.0 and your length (including 0.0, but not including the length). Casting to type int will truncate the result (so that the maxium value will be length  1).
(int)(Math.random() * myArray.length)
(int)(Math.random() * myArray.length)
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posted 10 years ago
Or use java.util.Random's nextInt(int n) method.
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posted 10 years ago
if you dont want to use any built in function then try this formula
Random no R(n) = (aR(n1) + b)mod n where a = any initial value , b= any offset and R is the previous Random no ,keep R(n1)=1 for the first case.It is also known as Linear congruential Generator .Check out Wikipedia for a detailed explanation.
Random no R(n) = (aR(n1) + b)mod n where a = any initial value , b= any offset and R is the previous Random no ,keep R(n1)=1 for the first case.It is also known as Linear congruential Generator .Check out Wikipedia for a detailed explanation.
Enjoy, Chander
SCJP 5, Oracle Certified PL/SQL Developer
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