This code fragment is quite confusing

[vijay shanker]

Hi all,

I am not able to undersatnd how output of this code generated by JVM.

public class Fizz {
public Fizz(){
System.out.println(x);
}
int x = 5;
public static void main(String[] args) {

final Fizz f1 = new Fizz();
Fizz f2 = new Fizz();
Fizz f3 = FizzSwitch(f1,f2);
System.out.println((f1 == f3) + " " + (f1.x == f3.x));
}
static Fizz FizzSwitch(Fizz x, Fizz y) {
final Fizz z = x;
z.x = 6;
return z;
}
}

Regards,
VIJAY SHAN

[fixed code tags]
[ February 16, 2008: Message edited by: fred rosenberger ]

[Ulf Dittmer]

Tell us what the output is, and what you do or do not understand about it.

[vijay shanker]

the out put is

true true


why is this output ?

[Ulf Dittmer]

The first "true" stems from the fact that f1 and f3 point to the same object (FizzSwitch returns the reference to f1, which then gets assigned to f3). Since "==" compares object references, they are equal. And since they point to the same object, naturally their "x" field is the same.

[Ilja Preuss]

Originally posted by vijay shanker:
the out put is

true true


why is this output ?

What output would you have expected?