Why final modifier has such impact
posted 8 years ago
You're not widening, you are narrowing. You would normally require a cast for the b = i; assignment. I can only presume that the compiler can tell that final int i = 2; implies the value of i will always be within the range of a byte. Try changing i to 128, and see whether it still works; 128 is outwith the possible range for bytes.
Jesper de Jong