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# HeadFirst Java, Ch3 Pool Puzzle

Greenhorn
Posts: 6
So I'm a little stumped...the following code produces this output:

triangle 0, area = 4.0
triangle 1, area = 10.0
triangle 2, area = 18.0
triangle 3, area = 28.0
y = 4, t5 area = 343

What has me stumped is the last line of output...I understand that both t5 and ta[2] are pointing to the same Triangle object, and that by setting ta[2].area = 343, t5.area will also = 343. But where does "y = 4" come from - if y = x, and x is set as 27, where is the value changed to 4? Any help would be appreciated, thanks!
[ May 26, 2008: Message edited by: Campbell Ritchie ]

Greenhorn
Posts: 20
It is straight forward.

After the while loop you are setting y = x where the value of x is 4 at that time. Later you changed the value of x to 27 but not �Y� so it printed value of y as 4.

Yong Lee
Greenhorn
Posts: 6
First, thanks for the fast reply!

Second, duh - I hadn't thought about the value of x as the loop was exited...for some reason, I thought that since x was given a new value, y took the same value. I see now that since the line "y = x" was written before "x = 27", y retains the previous value of x. Thanks!

Marshal
Posts: 65772
250
Please use code tags round quoted code; it makes it easier to read. I shall edit your post to add tags.

Yong Lee
Greenhorn
Posts: 6
Sure, will use code tags in the future. Thanks for the heads up.

Campbell Ritchie
Marshal
Posts: 65772
250

Originally posted by Yong Lee:
Sure, will use code tags in the future. Thanks for the heads up.

Thank you. You see how much better it looks with the code tags added. There are buttons below the "message" box for formatting your posts.

Greenhorn
Posts: 28
This is an old thread, but i also had a question.

But i am also having a trouble understanding the last part.

On line 17 and 18, y was 4, then the value changed to 27. but it had no influence on printing out y as 4(line21).
On line 19 and 20, t5=ta[2]. i am thinking t5=18 from previous area ta[2]. Then why all of sudden from line 20, t5.area changed to 343? should it not have any influence on t5 value, and print out 18 as area(line22) instead of 343?

sorry to bump the old thread, but someone please answer my question.

Thanks.

Ranch Hand
Posts: 163
Your first question is answered in this thread by Yong Lee.

As to your second question, ta[2] references a Triangle object. When you call

is a new object created, or does t5 reference the same object as ta[2]?

Ranch Hand
Posts: 42

Yong Lee wrote:So I'm a little stumped...the following code produces this output:

triangle 0, area = 4.0
triangle 1, area = 10.0
triangle 2, area = 18.0
triangle 3, area = 28.0
y = 4, t5 area = 343

What has me stumped is the last line of output...I understand that both t5 and ta[2] are pointing to the same Triangle object, and that by setting ta[2].area = 343, t5.area will also = 343. But where does "y = 4" come from - if y = x, and x is set as 27, where is the value changed to 4? Any help would be appreciated, thanks!
[ May 26, 2008: Message edited by: Campbell Ritchie ]

I realize this is an old post but I run the exact same code as above (chapter 3 HeadFirstJava),
and I receive the following :

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