# fourier image

mustakim

Greenhorn

Posts: 2

posted 8 years ago

Hi everybody! I'll appreciate help on the display of fourier image. I'm unable to get desired result. The portion of the java program is placed below:

void freq_spect(){

double F[][][];

double FX[][];

double f_r[];

double f_r1[];

double NNN[][];

double Four[][];

int fxy[][];

int wd=new_img.getWidth();//new_img is the bufferedimage.It's fourier image is to be displayed.

int ht=new_img.getHeight();

F=new double[wd][ht][2];

Four=new double[wd][ht];

FX=new double[wd][2];

f_r=new double[wd*ht];

f_r1=new double[wd*ht];

NNN=new double[wd][ht]; img_fourier=newBufferedImage(new_img.getWidth(),new_img.getHeight(),BufferedImage.TYPE_BYTE_GRAY);

rstr_f=img_fourier.getRaster(); //writable raster

for (int u=0;u<new_img.getWidth();u++)

{

for (int v=0;v<new_img.getHeight();v++)

{

NNN[u][v]=rstr.getSample(u,v,0); //rstr is the writable raster of the image.

NNN[u][v]=NNN[u][v]* Math.pow(-1,(u+v));

F[u][v][0]=0;

F[u][v][1]=0;

}

}

for (int u=0;u<new_img.getWidth();u++)

{

FX[u][0]=0; //real array

FX[u][1]=0; //imaginary array

for (int a=0; a<new_img.getWidth();a++)

{

for(int b=0;b<new_img.getHeight();b++)

{

FX[u][0]=FX[u][0]+(NNN[a][b])* Math.cos(Math.PI/180*( (6.28318*((u*a)/wd)));

FX[u][1] =FX[u][1]-((NNN[a][b])* Math.sin(Math.PI/180*( (6.28318*((u*a)/wd))));

}

}

}

vv=0;

for (int u=0;u<new_img.getWidth();u++)

{

for(int v=0;v<new_img.getHeight();v++)

{

for(int b=0;b<new_img.getHeight();b++)

{

//F[u][v][0] - real array

//F[u][v][1] - imaginary array.

F[u][v][0]=F[u][v][0]+(FX[u][0])* Math.cos(Math.PI/180*(6.28318*((v*b)/ht)))+(FX[u][1])* Math.sin(Math.PI/180*(6.28318*((v*b)/ht)));

F[u][v][1] =F[u][v][1]+(FX[u][1])* Math.cos(Math.PI/180*(6.28318*((v*b)/ht)))-((FX[u][0])* Math.sin(Math.PI/180*(6.28318*((v*b)/ht))));

}

double sum11=F[u][v][0]*F[u][v][0];

double sum22=F[u][v][1]*F[u][v][1];

Four[u][v]=(sum11+sum22);

f_r[vv]=Four[u][v];

f_r[vv]=Math.sqrt(f_r[vv]); //power spectrum

vv++;

}

}

for (int a=0; a<new_img.getWidth();a++)

for(int b=0;b<new_img.getHeight();b++)

{

rstr_f.setSample(a,b,0,Four[a][b]);

}

repaint();

}

[ May 30, 2008: Message edited by: mustakim ]

void freq_spect(){

double F[][][];

double FX[][];

double f_r[];

double f_r1[];

double NNN[][];

double Four[][];

int fxy[][];

int wd=new_img.getWidth();//new_img is the bufferedimage.It's fourier image is to be displayed.

int ht=new_img.getHeight();

F=new double[wd][ht][2];

Four=new double[wd][ht];

FX=new double[wd][2];

f_r=new double[wd*ht];

f_r1=new double[wd*ht];

NNN=new double[wd][ht]; img_fourier=newBufferedImage(new_img.getWidth(),new_img.getHeight(),BufferedImage.TYPE_BYTE_GRAY);

rstr_f=img_fourier.getRaster(); //writable raster

for (int u=0;u<new_img.getWidth();u++)

{

for (int v=0;v<new_img.getHeight();v++)

{

NNN[u][v]=rstr.getSample(u,v,0); //rstr is the writable raster of the image.

NNN[u][v]=NNN[u][v]* Math.pow(-1,(u+v));

F[u][v][0]=0;

F[u][v][1]=0;

}

}

for (int u=0;u<new_img.getWidth();u++)

{

FX[u][0]=0; //real array

FX[u][1]=0; //imaginary array

for (int a=0; a<new_img.getWidth();a++)

{

for(int b=0;b<new_img.getHeight();b++)

{

FX[u][0]=FX[u][0]+(NNN[a][b])* Math.cos(Math.PI/180*( (6.28318*((u*a)/wd)));

FX[u][1] =FX[u][1]-((NNN[a][b])* Math.sin(Math.PI/180*( (6.28318*((u*a)/wd))));

}

}

}

vv=0;

for (int u=0;u<new_img.getWidth();u++)

{

for(int v=0;v<new_img.getHeight();v++)

{

for(int b=0;b<new_img.getHeight();b++)

{

//F[u][v][0] - real array

//F[u][v][1] - imaginary array.

F[u][v][0]=F[u][v][0]+(FX[u][0])* Math.cos(Math.PI/180*(6.28318*((v*b)/ht)))+(FX[u][1])* Math.sin(Math.PI/180*(6.28318*((v*b)/ht)));

F[u][v][1] =F[u][v][1]+(FX[u][1])* Math.cos(Math.PI/180*(6.28318*((v*b)/ht)))-((FX[u][0])* Math.sin(Math.PI/180*(6.28318*((v*b)/ht))));

}

double sum11=F[u][v][0]*F[u][v][0];

double sum22=F[u][v][1]*F[u][v][1];

Four[u][v]=(sum11+sum22);

f_r[vv]=Four[u][v];

f_r[vv]=Math.sqrt(f_r[vv]); //power spectrum

vv++;

}

}

for (int a=0; a<new_img.getWidth();a++)

for(int b=0;b<new_img.getHeight();b++)

{

rstr_f.setSample(a,b,0,Four[a][b]);

}

repaint();

}

[ May 30, 2008: Message edited by: mustakim ]

posted 8 years ago

What is the desired result?

What is wrong with this code? Why do you think it doesn't work? does it compile? does it start then die? does it do nothing? does it do the wrong thing - and if so, what?

we're not here for you to dump your problem on and fix it for you. people will bend over backwards to HELP you, but nobody's gonna do it for you. the more info you can give us on what's wrong, the more likely you are to get help.

What is wrong with this code? Why do you think it doesn't work? does it compile? does it start then die? does it do nothing? does it do the wrong thing - and if so, what?

we're not here for you to dump your problem on and fix it for you. people will bend over backwards to HELP you, but nobody's gonna do it for you. the more info you can give us on what's wrong, the more likely you are to get help.

There are only two hard things in computer science: cache invalidation, naming things, and off-by-one errors

Campbell Ritchie

Marshal

Posts: 52581

119

mustakim

Greenhorn

Posts: 2

posted 8 years ago

I'm sorry that I could'nt post the topic correctly.Actually for a simple sinusoidal image with u=3 & v=0; using my code the resulting transforms are coming as zeroes.It should not be so. Thanks.

Campbell Ritchie

Marshal

Posts: 52581

119

Garrett Rowe

Ranch Hand

Posts: 1296

posted 8 years ago

That is really some pretty cryptic code.

This is a great time to learn that its very important to write code that other people can read and understand. Heck, in 6 months you might have to revisit this code and its important that

I have no idea what this method is doing, let alone why it's not doing it right.

This is a great time to learn that its very important to write code that other people can read and understand. Heck, in 6 months you might have to revisit this code and its important that

*you*understand it. Writing readable code means using meaningful names for your reference variables and in this case refactoring into smaller methods which do just one thing, and that have method names that convey exactly what it is they do.I have no idea what this method is doing, let alone why it's not doing it right.

Some problems are so complex that you have to be highly intelligent and well informed just to be undecided about them. - Laurence J. Peter

posted 8 years ago
There are only two hard things in computer science: cache invalidation, naming things, and off-by-one errors

agreed... variable names like 'F' and 'f_r ' are meaningless. nobody looking at your code would have any idea what these mean or are supposed to represent. And this:

FX[u][1]-((NNN[a][b])* Math.sin(Math.PI/180*( (6.28318*((u*a)/wd))));

is just impenetrable.

FX[u][1]-((NNN[a][b])* Math.sin(Math.PI/180*( (6.28318*((u*a)/wd))));

is just impenetrable.