problem with deployment

[Ranjan Pwar]

I have installed tomcat v5.5 but when i deployed my application by putting it under tomcat\webapp dir and try to run it from browser , it is showing error (resource not found)

[ujjwal soni]

Hi,

Check your configuration in web.xml file, if its a servlet then check that it maps properly to <servlet-name> <servlet-class> locations.

Could you post your web.xml file contents here ? Also check that the project type selected is a web application at the time of development.

Cheers!!!

Ujjwal B Soni

<baroda, gujarat, india>
<919998971048>

[Ranjan Pwar]

my web.xml:========


<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
version="2.4">

<servlet>
<servlet-name>Ch Submit</servlet-name>
<servlet-class>Submit</servlet-class>
</servlet>

<servlet-mapping>
<servlet-name>Ch Submit</servlet-name>
<url-pattern>/Submit.do</url-pattern>
</servlet-mapping>


<context-param>
<param-name>mainEmail</param-name>
<param-value>[e-mail]</param-value>
</context-param>

</web-app>

====
when i deployed my another application by placing it under tomcat/webapps/ dir , i am getting same exception when trying to run it from /manager

[ujjwal soni]

Hi,

Use below xml file & try.

<?xml version="1.0">

<servlet>
<servlet-name>Ch Submit</servlet-name>
<servlet-class>Submit</servlet-class>
</servlet>

<servlet-mapping>
<servlet-name>Ch Submit</servlet-name>
<url-pattern>/Submit.do</url-pattern>
</servlet-mapping>


<context-param>
<param-name>mainEmail</param-name>
<param-value>[e-mail]</param-value>
</context-param>

</web-app>


Many times, the encoding="ISO-8859-1"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
version="2.4" line creates a problem. Try removing it & redeploy your servlet on the container.

Cheers!!!

Ujjwal B Soni

[ujjwal soni]

Hi,


<?xml version="1.0" encoding="UTF-8"?>
<web-app>

<servlet>
<servlet-name>Ch Submit</servlet-name>
<servlet-class>Submit</servlet-class>
</servlet>

<servlet-mapping>
<servlet-name>Ch Submit</servlet-name>
<url-pattern>/Submit.do</url-pattern>
</servlet-mapping>


<context-param>
<param-name>mainEmail</param-name>
<param-value>[e-mail]</param-value>
</context-param>

</web-app>



Try using this web.xml file


Cheers!!!

Ujjwal B Soni

[Rene Larsen]

I would try to put the 'Submit' class in a package, and edit the <servlet-class> to the right 'package.to.add.Submit'

[William Brogden]

Rene is correct. ALL classes used in servlets should be in a package.

The reason is that the JVM looks in the "current directory" when trying to load a class in the default package and you have NO control over what the current directory is.

Any example you see that doesnt use a package is depending on the "invoker" servlet - see this ranch FAQ on the invoker.

Bill