manas ranjan mandal

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Posts: 97

posted 8 years ago

i don't understand the question... What do you mean by 'convert 1 into 0'?

if you are trying to convert it into a decimal number, each position represents a power of 2, just like decimal each position is a power of 10.

So the rightmost digit is 2^0, the next is 2^1, the next is 2^2, etc. you just add up the values where there is a 1. so if i had a four digit binary like "0111", i'd add up 2^0 + 2^1 + 2^2, which totals 7.

Does that help?

if you are trying to convert it into a decimal number, each position represents a power of 2, just like decimal each position is a power of 10.

So the rightmost digit is 2^0, the next is 2^1, the next is 2^2, etc. you just add up the values where there is a 1. so if i had a four digit binary like "0111", i'd add up 2^0 + 2^1 + 2^2, which totals 7.

Does that help?

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posted 8 years ago

If you want to convert all ones into zeros, why not just assign the value 0? That's your number with all ones converted to zeros ;)

If you also want to convert zeros into ones, there's an operator for that: ~. It returns the number with all bits flipped.

If you also want to convert zeros into ones, there's an operator for that: ~. It returns the number with all bits flipped.

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manas ranjan mandal

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Posts: 97

posted 8 years ago

Depending upon requirement i want to create method which read each bit and convert 1 into 0 and print that 32 bit pattern with 1 converted into 0.

Campbell Ritchie

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posted 8 years ago

Sounds like a use for Rob's suggestion with the ~ operator and a method in the Integer class which creates a String with the binary pattern in.

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