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unique key hibernate exception

 
sankar ramalingam
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Posts: 9
Eclipse IDE Java Spring
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hi professionals

I am using hibernate ,spring when i insert unique value at the time i got this exception
can any one give suggest how to handle this exception.


unique key hibernate exception

[size=18]



type Exception report

message

description The server encountered an inte rnal error () that prevented it from fulfilling this request.

exception

org.springframework.web.util.NestedServletException: Request processing failed; nested exception is org.springframework.dao.DataIntegrityViolationException: Could not execute JDBC batch update; nested exception is org.hibernate.exception.ConstraintViolationException: Could not execute JDBC batch update
org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:488)
org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:431)
javax.servlet.http.HttpServlet.service(HttpServlet.java:689)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)

root cause

org.springframework.dao.DataIntegrityViolationException: Could not execute JDBC batch update; nested exception is org.hibernate.exception.ConstraintViolationException: Could not execute JDBC batch update
org.springframework.orm.hibernate3.SessionFactoryUtils.convertHibernateAccessException(SessionFactoryUtils.java:622)
org.springframework.orm.hibernate3.HibernateAccessor.convertHibernateAccessException(HibernateAccessor.java:412)
org.springframework.orm.hibernate3.HibernateTemplate.execute(HibernateTemplate.java:378)
org.springframework.orm.hibernate3.HibernateTemplate.save(HibernateTemplate.java:639)
com.percipient.comp.trending.store.SpringHibernateTrendingStore.save(SpringHibernateTrendingStore.java:440)
com.percipient.comp.trending.store.SpringHibernateTrendingStore.addInterval(SpringHibernateTrendingStore.java:69)
com.percipient.comp.trending.impl.TrendingImpl.createInterval(TrendingImpl.java:228)
com.percipient.sample.bo.BOTrend.createTrendInterval(BOTrend.java:213)
com.percipient.sample.controller.TrendController.createTrendInterval(TrendController.java:295)
sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
java.lang.reflect.Method.invoke(Unknown Source)
org.springframework.web.servlet.mvc.multiaction.MultiActionController.invokeNamedMethod(MultiActionController.java:473)
org.springframework.web.servlet.mvc.multiaction.MultiActionController.handleRequestInternal(MultiActionController.java:410)
org.springframework.web.servlet.mvc.AbstractController.handleRequest(AbstractController.java:153)
org.springframework.web.servlet.mvc.SimpleControllerHandlerAdapter.handle(SimpleControllerHandlerAdapter.java:48)
org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:875)
org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:809)
org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:476)
org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:431)
javax.servlet.http.HttpServlet.service(HttpServlet.java:689)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)

root cause

java.sql.BatchUpdateException: Duplicate entry '9months' for key 2
com.mysql.jdbc.ServerPreparedStatement.executeBatch(ServerPreparedStatement.java:657)
org.hibernate.jdbc.BatchingBatcher.doExecuteBatch(BatchingBatcher.java:57)
org.hibernate.jdbc.AbstractBatcher.executeBatch(AbstractBatcher.java:174)
org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:226)
org.hibernate.engine.ActionQueue.executeActions(ActionQueue.java:136)
org.hibernate.event.def.AbstractFlushingEventListener.performExecutions(AbstractFlushingEventListener.java:274)
org.hibernate.event.def.DefaultFlushEventListener.onFlush(DefaultFlushEventListener.java:27)
org.hibernate.impl.SessionImpl.flush(SessionImpl.java:730)
org.springframework.orm.hibernate3.HibernateAccessor.flushIfNecessary(HibernateAccessor.java:390)
org.springframework.orm.hibernate3.HibernateTemplate.execute(HibernateTemplate.java:374)
org.springframework.orm.hibernate3.HibernateTemplate.save(HibernateTemplate.java:639)
com.percipient.comp.trending.store.SpringHibernateTrendingStore.save(SpringHibernateTrendingStore.java:440)
com.percipient.comp.trending.store.SpringHibernateTrendingStore.addInterval(SpringHibernateTrendingStore.java:69)
com.percipient.comp.trending.impl.TrendingImpl.createInterval(TrendingImpl.java:228)
com.percipient.sample.bo.BOTrend.createTrendInterval(BOTrend.java:213)
com.percipient.sample.controller.TrendController.createTrendInterval(TrendController.java:295)
sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
java.lang.reflect.Method.invoke(Unknown Source)
org.springframework.web.servlet.mvc.multiaction.MultiActionController.invokeNamedMethod(MultiActionController.java:473)
org.springframework.web.servlet.mvc.multiaction.MultiActionController.handleRequestInternal(MultiActionController.java:410)
org.springframework.web.servlet.mvc.AbstractController.handleRequest(AbstractController.java:153)
org.springframework.web.servlet.mvc.SimpleControllerHandlerAdapter.handle(SimpleControllerHandlerAdapter.java:48)
org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:875)
org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:809)
org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:476)
org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:431)
javax.servlet.http.HttpServlet.service(HttpServlet.java:689)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
[/size]
 
Reehan Lalkhanwar
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Posts: 106
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Hi Sankar,
I think there is some mistake in the uniqueness, as the error clearly states: "Duplicate entry '9months' for key 2"
Try making sure that the 'key 2' is unique.
If you still have issues, try posting the mappings and the code that saves to DB.
 
sankar ramalingam
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Posts: 9
Eclipse IDE Java Spring
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hi Reehan

Thank you for your kind reply. what i am asking .If i enter the unique value in my jsp at the time i want display alert like "already exist". The above exception came from hibernate i want handle exception in hibernate,so how to handle help me.
 
Reehan Lalkhanwar
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Go to the method: com.percipient.comp.trending.store.SpringHibernateTrendingStore.save()
Wrap line 440 in try - catch block.
Catch the exception: org.hibernate.exception.ConstraintViolationException
If this is caught it means that a duplicate entry was being inserted and so the error was thrown.

Hope that helps.
 
Fernando Giorgetti
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Reehan Lalkhan wrote:Go to the method: com.percipient.comp.trending.store.SpringHibernateTrendingStore.save()
Wrap line 440 in try - catch block.
Catch the exception: org.hibernate.exception.ConstraintViolationException
If this is caught it means that a duplicate entry was being inserted and so the error was thrown.

Hope that helps.


Helped, indeed!
 
Shriram Gopalakrishnan
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Yes catching ConstraintViolationException helps but is there a way to display the key name instead of key2. So for example instead of saying
"Duplicate entry '9months' for key 2" can it display or is there a way to display "Duplicate entry '9months' for duration" assuming duration is the unique
key.

The bottom line is if there are more than one columns which uses constraint and say for that matter unique constraint is there a way to display the key name/column name of which the
constraint was violated?

I tried getConstraintName() on ConstraintViolationException but it returned null.
 
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