a question about API Contents

[Rizvan Asgarov]

Hi friends,
I hope successes to everybody!
My question is such:


1. class Mutate {
2. public static void main(String [] args) {
3. StringBuilder s = new StringBuilder("012345678 ");
4. if (s.length() == 10)
5. s.insert(10, "abcdef");
6. s.delete(3,8);
7. System.out.println(s.indexOf("c"));
8. }
9. }

What is the result?

a. -1
b. 5
c. 6
d. 7
e. Compilation fails.
f. An exception is thrown at runtime.

one of my friend said me that the result must be "d. Compilation fails." .
but when i run this program the output shows 7
Can you please which one is true?
Sincerely,
Rizvan

[Abhi vijay]

Hi Rizwan, Please Quote the Source.

[Christophe Verré]

One of my friend said me that the result must be "d. Compilation fails."

Did you ask him why ?

[Rizvan Asgarov]

He said me that at the line of 5th incorrect...
Because the 10th index does not correspond "012345678 "

4. if (s.length() == 10)
5. s.insert(10, "abcdef");

Gratitudes at first!
Rizvan

[Abhi vijay]

There is a " " space after the digit 8, which makes the length()==10 true.
Hope this helps..

Please Quote the Source Rizwan.

[paddy Mahadeva Iyer]

well the answer is d.

Since there is a white space and the end of the original string and since we are using string builder here. That has to be the answer.

It will find the position of the value 'c' to be at 7.

[Rizvan Asgarov]

Dear friends,
Thanks for your response and times...
I have take this exam test: http://www.sun.com/training/certification/assessment/055-Jintro.jsp

I know s.length() == 10 is true but s.insert(10, "abcdef") isn't...
I think symbol 10 is not existing ("012345678 ")....(for insert method)

Since there is a white space and the end of the original string and since we are using string builder here.

You want to say that this is about string builder? (d. 7 or e. Compilation fails. )

Sincerely,
Rizvan

[Abhi vijay]

insert(10,"abcdef");
This means insert abcdef at the index position 10. which is after the space.

[Abhi vijay]

After inserting it will look like,
012345678 abcdef
then delete(3,8)
which gives 0128 abcdef.

[Abhi vijay]

So now guess what is the index position of alphabet "c".

[Rizvan Asgarov]

Dear Abhi vijay,

Thanks a lot......

I understood completely

but Forgive me that I know English a little also I use translation...therefore ...

Sincerely,
Rizvan

[Abhi vijay]

Thats perfectly fine, Rizwan.