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Greenhorn
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Hi everyone,

I have a list in the following format,
A, B, C, 3
X, Y, Z, 2
J, K, L, 4
P, L, M, 1

Now I need to sort this list based on the 4th index (integer). Can somebody tell me how can I go about it.

I've tried Collections.sort, but it doesnt help me when I have numbers greater than 9, like 10, it puts 1,10... etc.

Thanks.
 
Author
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Have a look at the Comparable and Comparator interfaces.
 
Pete Dawn
Greenhorn
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Can you give me an example. I need to find a quick fix to this one.

Thanks.
 
Sheriff
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Use String.split to get the last digit. Convert it into an integer using Integer.parseInt. Compare on the integer.
I'm sure you can turn this into code.
 
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