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# please explain me how the binarySearch method works in the below program?

Pooja Oza
Greenhorn
Posts: 21
Please explain me how the binarySearch method works normally and also in the below program?

import java.utils.Arrays.*;

public class BinarySearch
{
public static final int NOT_FOUND = -1;

/**
* Performs the standard binary search
* using two comparisons per level.
* @return index where item is found, or NOT_FOUND.
*/
public static int binarySearch( Comparable [ ] a, Comparable x )
{
int low = 0;
int high = a.length - 1;
int mid;

while( low <= high )
{
mid = ( low + high ) / 2;

if( a[ mid ].compareTo( x ) < 0 )
low = mid + 1;
else if( a[ mid ].compareTo( x ) > 0 )
high = mid - 1;
else
return mid;
}

return NOT_FOUND; // NOT_FOUND = -1
}

// Test program
public static void main( String [ ] args )
{
int SIZE = 8;
Comparable [ ] a = new Integer [ SIZE ];
for( int i = 0; i < SIZE; i++ )
a[ i ] = new Integer( i * 2 );

for( int i = 0; i < SIZE * 2; i++ )
System.out.println( "Found " + i + " at " +
binarySearch( a, new Integer( i ) ) );

}
}

The output is :

Found 0 at 0
Found 1 at -1
Found 2 at 1
Found 3 at -1
Found 4 at 2
Found 5 at -1
Found 6 at 3
Found 7 at -1
Found 8 at 4
Found 9 at -1
Found 10 at 5
Found 11 at -1
Found 12 at 6
Found 13 at -1
Found 14 at 7
Found 15 at -1

Please help me out with this, i am preparing for scjp exam and stuck with this method. I am really confused how a binarySearch() method works in Java, please explain me in detail

Rafael Angarita
Ranch Hand
Posts: 67
Hello Pooja,

Please remember to use code tags. It's very hard to read the code without it.

Cheers,

Pooja Oza
Greenhorn
Posts: 21

What is going on in this program? Could anyone please explain me the binarySearch() in simple way???

Ryan Beckett
Ranch Hand
Posts: 192
The iterative loop has a point mid (the middle element) and it compares it with the number your searching for. If the number is less than mid, during the next iteration the tail becomes mid, and the comparison is made again. If the number is greater than mid, the head becomes mid, etc. The data gets chopped by half every iteration, hence the term "Binary".

binarySearch(a, 11)

Itr
___lo_________mi_________high
1-> |0|1|2|3|4|5|6|7|8|9|10|11|12|
______________lo____mi____high
2-> |0|1|2|3|4|5|6|7|8|9|10|11|12|
___________________lo_mi__high
3-> |0|1|2|3|4|5|6|7|8|9|10|11|12|
_____________________lo_mi_high
4-> |0|1|2|3|4|5|6|7|8|9|10|11|12|

Found at index 11.

Always, remember the data must be sorted for the search to work. Otherwise, the search isn't guaranteed to work.
You can substitute your main method with this to see what I mean.

Good luck.

 Don't get me started about those stupid light bulbs.