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How to catch exception while validating the username and password of a hibernate.cfg.xml  RSS feed

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I do want to set the username and password dynamically in hibernate.cfg.xml

Here below is my configuration file.

Also im getting that session factory object like the below code.

So, in this above scenario, suppose if im giving the wrong password means exception should be caught and the string variable "GuigenserviceImpl.strAccpted" should be assigned to false.

But im getting the SQL Exception only in console like wrong username and password. And finally i couldn't able to catch the exception in Sessions class, static block.

Anyone can help me in catching that SQL Exception in my Sessions class and i need to handle that SQL Exception in my class.

Im getting this following exception message in my console.

Thanks in advance.

Thanks & Regards,
Kothandaraman N.
With a little knowledge, a cast iron skillet is non-stick and lasts a lifetime.
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