Post Increment question from Examulator.

[Marcelo DeOliveira]

public class Inc{
public static void main(String argv[]){
Inc inc = new Inc();
int i =0;
inc.fermin(i);
i = i++;
System.out.println(i);
}
void fermin(int i){
i++;
}
}

The answer is 0, But can anybody explain what's happening behind the scenes. Why it's not 1.
Thanks guys.

[fred rosenberger]

since java is pass by value, the whole method call is irrelevant. so, this boils down to the

i = i++;

for that, we have a FAQ that i can never find... but basically what happens is this.

the 'i' on the right is evaluated to 0 - we remember this.

We then increment i, since post-fix increments after evaluation. i is now 1.

we then assign the value we evaluated before - which is 0 - to i. i is now 0.

[Himalay Majumdar]

Post Increment