Opening a page with details about an item (servlet)

Apr 09, 2009 05:01:32

Hi!

I am trying to create a web application in java. I am using servlets. I have come to the stage where the user enters a search query and receives a list of items which match his/her query. When the user gets a list of items which match, how can I make it possible for the user to click on an item and it opens a "show" servlet page and this takes the information regarding the item and displays them in this page?

I have tried the below code but this occurs before the list even appears:

I don't know whats wrong.

Thanks for any replies

Apr 09, 2009 05:09:59

First of all this is a very bad practice. You should be using servlets only as controllers, and the view should be a JSP, or even a static HTML page with some AJAX. But either way, to get the result you need to display the results to the user in some table [which you are not doing], and the javascript invocation you are doing is wrong.

onClick='openItemDetails(itemToGet.getId())' should be changed to onClick='openItemDetails(<%=itemToGet.getId()%>)'

since itemToGet.getId() is a java object and not a javascript object.

Dawn.

Apr 09, 2009 06:43:31

do you know any good tutorials how to use servlets as controllers?

I'm sorry for my question - I'm still learning how to use everything

Apr 09, 2009 07:11:14

head first servlets and JSPs are my personal favourite....

Apr 09, 2009 07:55:30

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