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Abhay Agarwal
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Posts: 1376
Eclipse IDE Java
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Hi

I am not able to understand the behaviour of below mentioned codes
Pleasse explain

Code A -

public class Run {
public static void main(String[] args) {
System.out.print("A ");
final Object test = new Object();
synchronized (test) {
test.notifyAll();
}
System.out.println("B");
}
}
Output is - “A B”


========================

Code B -

public class Run {
public static void main(String[] args) {
System.out.print("A ");
synchronized (new Object()) {
new Object().notifyAll();
}
System.out.println("B");
}
}
Output - It prints “A ” and an exception is thrown





 
Ryan Beckett
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Posts: 192
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There are no other threads waiting for the monitor on your synchronized object, so main() continues to execute. When notifyAll() is called there are no other threads in the waiting state. So, the scheduler runs a thread in the Runnable state. main() is in the Runnable state.

In B,



You must call notifyAll() on a synchronized object. An IllegalMonitorStateException should have been thrown.
 
Don't get me started about those stupid light bulbs.
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