servletcontext.getRequestDispatcher(resource) throwing IllegalArgumentException

[Shaik Muhammad]

Hi,
I am trying to forward a httpservletrequest to a servlet from a controller servlet. When i call the method

   servletcontext.getRequestDispatcher(resource) 

with web.servlets.loginServlet as input parameter, this method throws IllegalArgumentException saying that the input parameter does not contain '/'. Please help.

[Christophe Verré]

with web.servlets.loginServlet as input parameter

It doesn't look like a path. Is it a named servlet ? If so, use getNamedDispatcher instead.

[Nishan Patel]

Hi,

Your syntax will like this...

 getServletContext().getRequestDispatcher("/gototrue.jsp").forward(request, response);   

[Ravindra Verma]

You can have request dispatcher object in two ways.
request.getRequestDispatcher("abc"); // #1
or
servletContext.getRequestDispatcher("/abc"); // #2

difference is when you use #1 server will look for the resource abc from current directory. In case of #2 it will start looking from context root so you need to put a '/' before your resource path. In case of #1 you may get in serious troubles sometimes you may need to put whole path like (http://localhost:8080:.........).

Regards
Ravindra

[Shaik Muhammad]

Thanks guys...It helped

[Brijesh Verma]

you can try this code

RequestDispatcher rd=getServletContext.getRequestDispatcher("input.jsp");
rd.forward(request,response);

[Harmanjit Singh]

When using request dispatcher from servlet context, the pathname must begin with a "/" and is interpreted as relative to the current context root.

    
RequestDispatcher rd=getServletContext.getRequestDispatcher("input.jsp"); 
rd.forward(request,response);

Above code will cause IllegalArgumentException