for each loop and array

[avi sinha]

   
int []arr = {1,2,3,4};
for ( int i : arr )
{
   arr[i] = 0;
}
for ( int i : arr )
{
   System.out.println(i);
} 

output as per the solution is: 0 0 3 0

when i solved i thought
first loop:
a[1]=0
a[2]=0
a[3]=0
a[4]=0 ArrayIndexOutOfBounceException

ranchers please tell me where am i wrong ?? this question is from john mayer's mock exam

avi sinha

[Himanshu Gupta]

See carefully the content of your array provided there. The content of array is changing within loop.

the loop will execute the following code:

a[1]=0
a[0]=0
a[3]=0
a[0]=0

[kaushik vira]

This Example is from Inquisition.

Might this can help you..


First loop :-i=1 and arr = {1,2,3,4}
arr[1] = 0; and arr becomes {1,0,3,4}
--------------------------------------------
sec loop :-i=0 and arr = {1,0,3,4}
arr[0] = 0; and arr becomes {0,0,3,4}
--------------------------------------------
Third loop :-i=3 and arr = {0,0,3,4}
arr[3] = 0; and arr becomes {0,0,3,0}
--------------------------------------------
Fourth loop :-i=0 and arr = {0,0,3,0}
arr[0] = 0; and arr becomes {0,0,3,0}
--------------------------------------------
--------------------------------------------

final output - {0,0,3,0}

[avi sinha]

thanks everyone my mistake ........ m such a fool