Primitive Assignments

[Pooja Sinha]

Line 1 : byte a = 3;
Line 2 : a+= 7L;

The compiler automatically puts a cast in line 1. Will the second line run fine or will it require an explicit cast?
In case we require an explicit cast for long to byte (even though after the addition the value will easily fit into a byte), why don't we require an explicit cast in line 1 where also we are narrowing??

Please help me understand this.

[Lucas Smith]

byte a = 3;
a += 7L;

is equivalent to:
byte a = 3;
a += (byte)7L;

But:
byte a = 3;
a = a + 7L; //compiler error

+= operator makes implicit cast

[Pooja Sinha]

In that case,

Why does byte a = 3 work fine but not byte a = 7L?

Why does the compiler automatically casts the first expression and not the second?

[Lucas Smith]

Look at the Java Language Specification - long has special treatment.

[karthick chinnathambi]

Lukas Smith wrote:
+= operator makes implicit cast

Not only +=, all extended assignment operators put in an implicit cast..........

[Lucas Smith]

It's logical.

[karthick chinnathambi]

Lukas Smith wrote:It's logical.

s my friend........

just wanted to mention that point.......

[Ankit Garg]

karthick chinnathambi wrote:
s my friend........

What's "s"?? is it yes?? if yes, then try to Use Real Words when you post anything...