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String split()

 
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Hi All,
I want to split string into diff parts



Expected out put is: welcome
to
java
world

I want to eleminate all special character in my string, where as in split we can mention any one character to check in string. how can I do this.
 
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What did you find when you perused the String javadoc?
 
Reshma Reddy
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bear,
I couldn't get any thing about my requirement, give me any clue to slove this
 
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Hi Vardhan,

use regex pattern.

Make one pattern which contains your special character. If your string contains this character split it.

May be Regix pattern will help you...
 
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Why specify your own special characters? There are special character classes that represent all actual letters or punctuation characters; check out the API of java.util.regex.Pattern for more info.
 
Greenhorn
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StringTokenizer will help you.
Below is the code:
String name = "welcome@ to$ java world!";
StringTokenizer tokenizer = new StringTokenizer(name,"@ $");
while(tokenizer.hasMoreTokens()){
System.out.println(tokenizer.nextToken());
}

 
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Try this:
 
Reshma Reddy
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thanks zhid,

it is working perfect..
 
Rob Spoor
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I'd prefer the character class [\s\W]. \s means whitespace ([ \t\n\x0B\f\r]), whereas \W is a synonym for [^\w] and \w is a synonym for [a-zA-Z_0-9]. Of course you can't use * since then all empty strings between all characters will match as well; the regex will be [\s\W]+. And because \W implies \s, \W+ will suffice.

Of course, once you start using other word characters like é you will run into problems, since that also matches \W.
 
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