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Greenhorn
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I have several solution for this case actually. I just want to ask if this code "sexy" enough.
If you have suggestion, i really appreciate it...


Thanks...
 
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Hi Alfonz,

I don't think this algorithm is too "sexy". It's very inefficient. You use a for loop in a for loop which runs through the text again and again and you do other unnecesseary operations.
You can do the counting part with one for loop and a Map. You run through the text with the loop and for every character you have 2 options:
1, Character not in the map, you put it into the map with a value of 1.
2, The Map contains the chraracter: You increment the stored value by one.
From the map you know the:
-number of different characters
-which are these characters
-how many of them you have
So you have all the necesseary information.
I hope it helps.
 
Alfonsus Hartanto
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thanks for the solution... its cool man...
 
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