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Math.PI comparision

 
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Any idea why this condition fail due to missing precision


Thanks
 
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Don't know what you mean; the code will compile, and the comparison will succeed. Do you observe otherwise? Tell us more details.
 
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What happens depends on what is in between.
 
vu lee
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In debug mode, I saw the value of one variable was 3.14159265358979323846 but the other was 3.1415926535897. It didn't happen all the time though.
 
Campbell Ritchie
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Those figures from debug mode might not be precise. Is there any code which does arithmetic with pi in that block?
 
vu lee
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Neither synchronized nor Lock, but the comparision occured in different thread. I'm in training, will post my code.

Thanks


 
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You should hardly ever use == or != with flout or double comparison, just because of the missing precision. The following is better:
Another option is using Double/Float.compare:
 
Campbell Ritchie
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I tried that last night with a little arithmetic in between, and in all cases the two values appeared to be identical; it didn't print ???

But there might be something in between the lines shown which alters the value of pi; please tell us the details of what you are doing with pi in the interim.

And that is a splendid spelling error, Rob
 
vu lee
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Thanks Rob. The Double.compare() has resolved my issues.
 
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