Understanding inheritance

[Bhaskar Mukhejee]

Hi All,

I have started java recently. Got a snippet of a code. can anybody please explain this inheritance?
I have got 2 classes Test1 and Test2. Test1 inherits Test2.

public class Test2 {
	int i =40;
	
	void math(){
		System.out.println("Executing method of Test2");
	}
}

public class Test1 extends Test2{
	int i = 20;
	public static void main(String[] args) {
		Test1 t = new Test1();
		System.out.println(t.i);
		t.math();		
	}
	
	void math (){
		System.out.println("Executing method of Test1");
	}

}

The output is :
20
Executing method of Test1

but when I am replacing Test1 with Test2 The output is :
40
Executing method of Test1

It is showing accessing the instance variable of Test2 class but method of Test1 class why?

Please help. Thank you.

Regards,
Bhaskar

[Vivek Singh]

Bhaskar Mukhejee wrote:

but when I am replacing Test1 with Test2 The output is :
40
Executing method of Test1

  Test2 t = new Test1();  

Is this what you have done.

Regards,
Bhaskar

So here t refers to Test2 But at runtime the instance is created of Test1 so it overrides the math method of Test1.

[Embla Tingeling]

Bhaskar Mukhejee wrote:It is showing accessing the instance variable of Test2 class but method of Test1 class why?

It's because variables aren't overridden, only methods are.

[Campbell Ritchie]

This FAQ might help you.

[Bhaskar Mukhejee]

Thanks to all of you for this help.

Regards,
Bhaskar