Why service method doesn't run?

[anarkali perera]

package voter.servlet;

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class content extends HttpServlet {

	public content() {
		System.out.println("ctor");
	}

	public void doPost(HttpServletRequest request, HttpServletResponse response)
			throws ServletException, IOException {
		this.doGet(request, response);
	}

	public void doGet(HttpServletRequest request, HttpServletResponse response)
			throws ServletException, IOException {
		System.out.println("doGet");
	}

	public void service() {
		System.out.println("service");
	}

	public void init() {
		System.out.println("init");
	}

	public void destroy() {
		System.out.println("destroy");
	}

}

when i run this it gives

ctor
init
doGet

as result.Why service method doesn't run?

[Paul Clapham]

See my answer on your crosspost.

[Bear Bibeault]

I've copied Paul's answer below and removed the other post.

Paul Clapham wrote:Some other method named service() with different parameters will have run.

[Praneeth Thiruveedhula]

hi,
in your program that service method is just like normal method.that method does't contain any parameters and does't throws any exception. so that is just like normal method. bydefault that method won't executes,and you have to call explacitly.

if you wrote the service method as follows then it may executes bydefault.

public void service(ServletRequest request,ServletResponse response)throws ServletException
{
System.out.println("javamirchi");
}

[Ashwin Bangar]

the service method you have written is an ordinary method and wont be called by the servlet container.
it is as if you have given a return type to constructor and hoping it to execute when you follow an object creation process.