xsl:include replaces previous defined xsl:template?

K. Tsang

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posted 15 years ago

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Hello all,

I have a little trouble getting xsl:include to work in my xslt file. The code looks like this:

The whole idea is to separate the header and footer files for easy changes. But when I run the page, the footer.xsl content "always" show up. The header or footer xsl file looks like this:

Does the <xsl:include> replaces the <xsl:template> portion? How to fix this include problem? The header and footer files are static html, I should also able to include "header.html" instead by setting the mime type to "xhtml+xml".

Any one have ideas? Thanks.

K. Tsang CEng MBCS PMP PMI-ACP OCMJEA OCPJP

Paul Clapham

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posted 15 years ago

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No, <xsl:include> includes the templates from its href reference into the program. So the net result of your two <xsl:include> elements is that you now have a program with three templates, all of which have match="/". At this point the priority rules come into play, but there isn't much point in going into that because I don't think that was what you wanted.

So before you try to "fix" anything, it would probably be a good idea for you to go back and review how it works. What you have there appears to have been based on an incorrect understanding and I think you need to start over again.

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