why does value not change???

[maggie karve]

What is the output of this program ?

public class Sharpen
{ 
    String name="FunnyMan";
    public static void main(String [] args)
    {
        new Sharpen().go();
    }
    public void go()
    {
        Pencil pencil = new Pencil(this);
        pencil.getSharpen().setName("seizure");
        pencil.deleteSharpen(pencil.getSharpen());
        System.out.println(pencil.getSharpen().getName());
    }
    public void setName(String name_INP)
    {
        name = name_INP;
    }
    public String getName()
    {
        return name;
    }
}class Pencil
{
    Sharpen sharpen;
    public Pencil(Sharpen sharpen_INP)
    {
        sharpen = sharpen_INP;
    }
    public Sharpen getSharpen()
    {
        return sharpen;
    }

    public void setSharpen(Sharpen sharpen)
    {
        this.sharpen = sharpen;
    }
    
    void deleteSharpen(Sharpen sharpen)
    {
        sharpen = null;
        sharpen = new Sharpen();
        sharpen.setName("mothulla");
    }
}

Choose: 1

Options

1.) FunnyMan

2.) seizure

3.) mothulla

4.) NullPointerException

5.) Compile time error

answer is seizure..i expected it to be mothulla...since the set method calls setname method and sets it value to mothulla....
if anybody has understood kindly explain..thanks in advance

[Lokesh Varma]

void deleteSharpen(Sharpen sharpen)
{
sharpen = null;
sharpen = new Sharpen();
sharpen.setName("mothulla");
}

In the above function the argument "sharpen" is local to method. It is shadowing the instance variable "sharpen". You are making local variable to NULL. change the argument to any other name as shown below:

void deleteSharpen(Sharpen sharpen1).....you will get output "mothulla"