why does method get called twice though it is called only once?

[maggie karve]

class A1{
	A1(){
		System.out.println("A1");
			show();
	}
	public void show(){
		System.out.println("showing");
	}
}
public class Checking extends A1{
	Checking(){
		System.out.println("Checking");
	}
	String name="abc";
	int age=12;
	boolean value=true;
	public void show(){
		System.out.println(name+age+value+"name age and values are printed");
	}
public static void main(String[] args){
	A1 a1=new Checking();
	a1.show();
	
}
}

here first superclass constructor is called then it invoked method of subclass then again subclass constructor is called then why again the method is called though i didnt call the method in subclass constructor???

i expected the output to be
A1
null0falsename age and values are printed
Checking
but the output is A1
null0falsename age and values are printed
Checking
abc12truename age and values are printed

[Rajiv Chopra]

because of

a1.show();

at line 22

[Pramod P Deore]

when you write

   
A1 a1=new Checking()
 

then constructor of subclass is called which call constructor of super class i.e A1() which prints

   
A1
 

then this constructor call show method which prints

  
null0falsename age and values are printed
 

after super class constructor completes subclass constructor i.e(class Checking ) constructor runs and prints

  
Checking
 

After completing subclass constructor you call method show() which prints

  
abc12truename age and values are printed