Java array help

[Tracie Marshall]

So, I have this code and I have an array of alphabets which I've copied into a new array. No I need to go through the array and print the vowels "a,e,i,o,u" in uppercase. I was wondering if anyone could help me.
Thanks!

  public class Alphabet {

	// Fill an array with the alphabet
	private static String[] alphabet = { "a", "b", "c", "d", "e", "f", "g",
		"h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t",
		"u", "v", "w", "x", "y", "z" };
	private static String[] alphabet2 = new String[alphabet.length+1];
	// Main
	public static void main(String[] args) {
		// Scanner
		Scanner console = new Scanner(System.in);
		// Asks the user for a position in the alphabet between 0 and 25
		System.out.println("Select the position to print by entering a value between 0 - 25");
		// Finds the index
		int theIndex = console.nextInt();
		// Prints the requested position and the letter at the position
		System.out.println("The letter of the alphabet at position "+ (theIndex) + " is : " + alphabet[theIndex]);
		System.arraycopy(alphabet, 0, alphabet2, 1, alphabet.length);
		System.out.println("The letter of the alphabet at position "+ (theIndex) + " is : " + alphabet2[theIndex]);
		for(int i = 0; i < alphabet2.length; i++){
			if(){
				
			}
		}

	}
}  

[Sebastian Janisch]

I don't really get the sense of it but this should help

first, your array should be of type char and not String...

you can also iterate over the array using the enhanced for loop .

for(char c : alphabet2)
{
    switch(c)
    {
        case 'a':
        case 'e':
        case 'i':
        case 'o':
        case 'u':
            System.out.println(String.valueOf(c).toUpperCase());
    }
}

[Wouter Oet]

I don't get it either. Why are you using an arraycopy?
But instead of String.valueOf(c).toUpperCase() I would use Char.toUpperCase(c);