CertPal Q61 - Which will be OVERRIDDEN?

[Simran Dass]

In the foll. code both the Fringe and Bread interfaces have the eat() method.
Which method is being overridden at line #3 ? Cannot understand why the code
gives Compiler Error. Bec' the implements clause has Fringe first does it not mean
that test implements eat () of interface Fringe ?

public class test implements Fringe , Bread // #5
  {
     public static void main(String[] args)
     {
         Fringe best = new test (); // #1
         best.eat();// #2
     }
    
     public void eat() throws Exception // #3
     {
        System.out.println("Test");
        throw new Exception(); // #4
     }
  }

  interface Fringe 
  {
      public void eat() throws Exception ; 
  }

  interface Bread
  {
       public void eat() throws  MyException;
  }

  class MyException extends RuntimeException{}

[Ankit Garg]

Actually you are overriding the eat method of both Fringe and Bread. This behavior is defined in the JLS. Basically since you are overriding both the eat methods, so the throws clause in the overriding method must have the most restrictive exceptions declared. Here since one eat method has Exception and the other MyException in the throws clause, so your eat method is allowed to throw MyException but not Exception...

[Guilherme Borges Lima]

Which method is being overridden at line #3 ?

Both methods are being overriden. You cannot throw Exception because eat() of interface Bread does not throw Exception. In this case you just can throw something that is IS-A RunTimeException(or a Error).
When you implement a interface you must implement all its methods. No matter how many interfaces has the method eat(), you must implement eat() for all the interfaces.

Bec' the implements clause has Fringe first does it not mean
that test implements eat () of interface Fringe ?

No, the order does not matter.

[Simran Dass]

Got it. Quick reply.

[Jeevan Reddy]

I had just started watching the thread.
Prompt comes Ankit's reply. Lovely.

Thanks Ankit