ExamLab for sjcp 6.0 wrote:
A question from ExamLab for sjcp 6.0:
Which one is the valid statement?
A int[] it1 = new int[0]{};
B new int[2];
C int[] it2 = new int[][]{{1}}[0];
D int[][] it3 = new int[]{0}[0][0];
E int it5 = new int[2]{}[]
The answer is C.
Doesn't it covert from int[][][] to int[] ?
And about answer D, the explaination says it coverts from int[] to int[][]. Why doesn't it actually covert int[][][] to int[][] ?
code is assigning a one dimensional array to one dimensional array. int[][]{{1}}[0] is creating a two dimensional array and initializing the first dimension only then the code is using the [0] operator to get the array at 0th location and array will be one dimension array. So it is legal to assign it to one dimension array.
int[][] it3 = new int[]{0}[0][0]; is not legal because [0][0] will give us the element at that location. That element will be of type int and we can not assign an int to an array.
A- It is creating an anonymous array. You cannot specify the dimension when you create an anonymous array. So statement A is invalid.
C- It is creating a two dimensional anonymous array and it is assigning the first array that is the 0 one to the one dimension array which
is perfectly legal. Because 2-D arrays are array or arrays.
E- has the same problem an anonymous array can't have dimensions mentioned.
Harpreet Singh janda wrote:It does not convert int[] to int[][].
A 2 dimensional array is as array of arrays.
code is assigning a one dimensional array to one dimensional array. int[][]{{1}}[0] is creating a two dimensional array and initializing the first dimension only then the code is using the [0] operator to get the array at 0th location and array will be one dimension array. So it is legal to assign it to one dimension array.
int[][] it3 = new int[]{0}[0][0]; is not legal because [0][0] will give us the element at that location. That element will be of type int and we can not assign an int to an array.
A- It is creating an anonymous array. You cannot specify the dimension when you create an anonymous array. So statement A is invalid.
C- It is creating a two dimensional anonymous array and it is assigning the first array that is the 0 one to the one dimension array which
is perfectly legal. Because 2-D arrays are array or arrays.
E- has the same problem an anonymous array can't have dimensions mentioned.