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how the compiler chooses a method from overloaded methods?

 
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in occasions like this when there is no exact match how does the compile choose one method?
what does the compiler take in to account when saying that the call to method is "ambiguous"(is it the number of widening operations)?
thanks
 
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this kind of question discussed here many time. search here
 
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Kevinn please post here if you find the answer, anyway your code does not compile.

Thanks.
 
kevinn lee
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I couldnt find.can some one help
thanks
 
kevinn lee
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Emanuele Ghe wrote:Kevinn please post here if you find the answer, anyway your code does not compile.

Thanks.


yeah it doesnt compile.
thanks
 
Seetharaman Venkatasamy
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https://coderanch.com/t/241415/Programmer-Certification-SCJP/certification/Overloaded-Method-Call#1124087

 
Seetharaman Venkatasamy
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understand? I ask you one question

you will get compilation error[ambiguous eference to a method] at this statement * m(c, c); * . to remove error you have to modify this statement. how will you do that?
 
kevinn lee
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Seetharaman Venkatasamy wrote:understand? I ask you one question

you will get compilation error[ambiguous eference to a method] at this statement * m(c, c); * . to remove error you have to modify this statement. how will you do that?



thanks a lot
compiles
 
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Hello,

Snippet taken from JLS and your code snippet where the ambiguity has appeared



This is where the ambiguity is happening. That's why you have to change like this


Because compiler is unable to decide and such a situation is causing ambiguity.

Hope this helps,
 
kevinn lee
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thanks prithvi
 
Prithvi Sehgal
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Hello,

Mate you are always welcome. From this we are learning also.

Keep rocking,
 
Don't get me started about those stupid light bulbs.
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