Print Statement help

[Shae Weathers]

I recently wrote a program will print out the spelling of numbers between 0-25 when inputted, now I need to figure out how to get the program to print out the statement "out of range" when a number is entered outside of that range. I tried using the if else statement, but I kept getting an error message. This is what I have so far:

public class Say
{

static String number[];

public static void main( String[] args )
{
number = new String[26];
number[0] = "zero";
number[1] = "one";
number[2] = "two";
number[3] = "three";
number[4] = "four";
number[5] = "five";
number[6] = "six";
number[7] = "seven";
number[8] = "eight";
number[9] = "nine";
number[10] = "ten";
number[11] = "eleven";
number[12] = "twelve";
number[13] = "thirteen" ;
number[14] = "fourteen";
number[15] = "fifteen";
number[16] = "sixteen";
number[17] = "seventeen";
number[18] = "eighteen";
number[19] = "nineteen";
number[20] = "twenty";
number[21] = "twenty-one";
number[22] = "twenty-two";
number[23] = "twenty-three";
number[24] = "twenty-four";
number[25] = "twenty-five";



int n = Integer.parseInt( args[0] );
System.out.println( number[ n ] );
}

}

[Seetharaman Venkatasamy]

your code doesnt handle the Exception.

Note : please use code tag while posting your code, so that it can be easy to read.

[David Patrzeba]

 
//inside main following opening curly brace
if(Integer.parseInt(args[0]) > 25 || Integer.parseInt(args[0]) < 0){
     System.out.println("Out of Range: Number must be between 0 and 25 inclusive");
     System.exit(0);
}

[Shae Weathers]

Thank you so much! I eventually came up with the solution shortly after posting the question

[David Patrzeba]

Your welcome.

Obviously this is the simple answer which you can improve by adding a while loop around the statement that allows the user to retry his input if he fails the evaluation.

[Christophe Verré]

David Patrzeba wrote:

 
//inside main following opening curly brace
if(args[0] > 25 || args[0] < 0){
     System.out.println("Out of Range: Number must be between 0 and 25 inclusive");
     System.exit(0);
}

Is this how you compare strings ?

[David Patrzeba]

Oh wow....yea way wrong...i'll fix that right now. I really shouldn't post when I'm tired

[fred rosenberger]

Also, we prefer if you don't just hand out the solution. Many of the questions here are homework assignments, and giving someone the solution doesn't help them learn. Even worse, if they submit your solution as their own, or if it even LOOKS like they handed in your solution, many schools would consider that a breach of ethics (plagiarism/cheating) and the student could be disciplined and potentially expelled.

[David Patrzeba]

Good to know, I'll avoid giving out direct answers like that in the future.