OK, let's have a clue: this(args) call the overloaded constructor of the class. In your case this() calls the no-args constructor of the same class! Try it, you'll get it!
|BSc in Electronic Eng| |SCJP 6.0 91%| |SCWCD 5 92%|
this() is used call the another constructor (as per passed arguments) of the same class and super is used to call superclass constructor. What you have not understand in this?
Life is easy because we write the source code.....