2 objects EXCEPTION

[Arun C. Giridharan]

class A {
	void m1(int x, int y) throws ArithmeticException,
			ArrayIndexOutOfBoundsException {
		try {
			int z = x / y;
		}
		// catch(ArithmeticException e){e.printStackTrace();}

		finally {
			int a[] = new int[7];
			a[7] = 1;
		}// e.getMessage();}
		{
			System.out.println("ArithmeticException");
		}
	}
}

class DriveA {
	public static void main(String cmd[]) {
		A a = new A();

		// ArithmeticException e=

		try {
			// new ArithmeticException(); .....UNABLE TO CREATE EXCEPTION
			// OBJECT...WHICH CAN BE HANDLED BY catch block
			a.m1(0, 0);// a.catch(e);
		} catch (ArithmeticException e) {
			System.out.println("ArrayIndexOutOfBoundsException...MAIN() ");
		}
		System.out.println("End of main() ");
	}
}

ONly 1 exception is thrown out ....


output :
ArrayIndexOutOfBoundsException...MAIN()
End of main()

[Christophe Verré]

UseCodeTags the next time you post some code. I've also indented your code, because this is hardly readable.
And clearly tell what your problem is !

[Arun C. Giridharan]

Thank you Verré ! ...

[Christophe Verré]

Can you explain why you expect more than one exception ?

[Campbell Ritchie]

The throws declaration means it might throw an ArithmeticException or an ArrayIndexOutOfBoundsException, not both.

By the way: it is not usually necessary to declare unchecked Exceptions; those ought to be described with @throws tags in the documentation comments instead.

[Abimaran Kugathasan]

Arun Giridharan wrote:
output :
ArrayIndexOutOfBoundsException...MAIN()
End of main()

The exception thrown in the finally block overruled the exception which thrown in the try block. Have a look on this link

[Campbell Ritchie]

Abimaran Kugathasan wrote:The exception thrown in the finally block . . .

What Exception in the finally block? I can see no Exception in the finally block.

[Abimaran Kugathasan]

Campbell Ritchie wrote:

Abimaran Kugathasan wrote:The exception thrown in the finally block . . .

What Exception in the finally block? I can see no Exception in the finally block.

Is it?

         // catch(ArithmeticException e){e.printStackTrace();}  
   
         finally {  
             int a[] = new int[7];  
             a[7] = 1;// What about this line....  
         }// e.getMessage();}  
         {  .......

Won't ArrayIndexOutOfBoundsException be thrown?

[Campbell Ritchie]

Abimaran Kugathasan wrote: . . . Won't ArrayIndexOutOfBoundsException be thrown? . . .

Yes, sorry, I missed that.

[Abimaran Kugathasan]

Campbell Ritchie wrote:Yes, sorry, I missed that.

Thanks.

[Arun C. Giridharan]

Java Fails to handle two Exception Objects ONLY ArrayIndexOutOfBoundsException is thrown ...ON THE ABOVE EXAMPLE ...

[Abimaran Kugathasan]

Arun Giridharan wrote:Java Fails to handle two Exception Objects ONLY ArrayIndexOutOfBoundsException is thrown ...ON THE ABOVE EXAMPLE ...

Did you go through the link which I gave you? They intently do this.

[Arun C. Giridharan]

They intently do this.

but it doesn't make any sense ....why overruled come into picture ... (or is it some kind of rule ???)

[Abimaran Kugathasan]

Arun Giridharan wrote:but it doesn't make any sense ....why overruled come into picture ... (or is it some kind of rule ???)

OK, then If I asked, what do you do with those two exceptions?

[Arun C. Giridharan]

Exception are meant to be handled (of corresponding one) ! through Structured way