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Generics and method compareTo giving me a warning  RSS feed

 
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Hello there i'm very new to learning about Generics. There is an exercise in Java How to Program by Paul and Harvey Deitel where i'm supposed to rewrite a method used in an earlier example but as a generic method. I've done it and it works fine but i keep getting this warning...

Note: GenericSelectionSort.java uses unchecked or unsafe operations.
Note: Recompile with -Xlint:unchecked for details.


So i recompile with Xlint and it say the following...


GenericSelectionSort.java:22: warning: [unchecked] unchecked call to
compareTo<T> as member of raw type java.lang.Comparable

Here is the code



So the problem is where i'm trying to use the compareTo method but i don't understand why. I mean the method makes sure that the array implements the Comparable interface. Can anyone point out what i'm doing wrong please?
 
Sheriff
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Comparable is generic as well. So your <T extends Comparable> should be <T extends Comparable<T>> or even better <T extends Comparable<? super T>>. This second form allows you to use classes like java.sql.Date, since java.sql.Date indirectly implements Comparable<java.util.Date>, not Comparable<java.sql.Date>.
 
Neil Cartmell
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Rob Prime wrote:Comparable is generic as well. So your <T extends Comparable> should be <T extends Comparable<T>> or even better <T extends Comparable<? super T>>. This second form allows you to use classes like java.sql.Date, since java.sql.Date indirectly implements Comparable<java.util.Date>, not Comparable<java.sql.Date>.



Thank you! i can't believe i didn't spot that as i'm looking right at examples using compareTo! Oh well problem solved, thanks for your help.
 
Marshal
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It's not something you know until you see it written down.
 
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