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using regular expression Problem

 
Mohit G Gupta
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"\\w\\s*"-it finds first position Tobe a word then followed by a space



output:


start string eend
0 0
1 1
2 2
3 3
4 4
5 5


i think output should be
start string end
0 a 2
2 1 4
4 4
5 5

why it isn't finding a followed by space as it matches (\\w\\s)*?
and 1 followed by space
then what's the use ? in the regular expression..


if i remove ? ,it finds "a 1 2"
 
Gari Jain
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I cannot understand the question?



What is that...a loop?
 
Mohit G Gupta
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these types of question come in OCPJP.
that's why i posted it
 
Mohit G Gupta
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Please somebody help
i had posted the question about 3 days ago
i haven't got a correct answer

 
Sumit Khurana
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* is a greedy quantifier and *? is reluctant quantifier.
greedy quanitifier first go through the source and than come back and find the things.so,it knows all the source...
but *? operator is unwilling to do anything it prints the things in single go....it always do the easier things....*? means zero or more and it does not know about the things which will come after the current word....so,easier thing for it is to find zero.....
 
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