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Difference between String s

 
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Difference between 1.string s="raja"; and 2. string s=new String("raja");
what i read is , only one instance and one reference created for first case. Two instances and one
reference created for second case. Object created in constant memory for first case.
Object created in heap memory for second case.
My question is in general how many objects for both.
 
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Hi

Just refer following URl

http://www.javabeginner.com/learn-java/java-string-comparison
 
Rajendra Prakash
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No , i am not clear. 1) String s=new String("raj"); for this code one object created in heap memory
and one object created in String pool.(String pool is also in heap memory ah
2) String s="raj"; for this code one objected created in string pool only .
Is it right or wrong. If wrong how
 
Rajendra Prakash
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I am getting different comments from google. Is it correct

In case of s1 2 objects will be formed one in heap memory while other in string constant memory.
In case of s2 1 object will be formed in string constant memory.
 
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This Journal article should interest you.
 
With a little knowledge, a cast iron skillet is non-stick and lasts a lifetime.
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