public class ThreadDemo extends
Thread {
public void run() {
for(int i = 0; i < 5; i++) compute();
}
public static void main(
String[] args) {
ThreadDemo thread1 = new ThreadDemo();
Thread thread2 = new Thread(new Runnable() {
public void run() { for(int i = 0; i < 5; i++) compute(); }
});
if (args.length >= 1) thread1.setPriority(Integer.parseInt(args[0]));
if (args.length >= 2) thread2.setPriority(Integer.parseInt(args[1]));
thread1.start();
thread2.start();
for(int i = 0; i < 5; i++) compute();
try {
thread1.join();
// thread2.join();
} catch (InterruptedException e) {}
}
static ThreadLocal numcalls = new ThreadLocal();
static synchronized void compute() {
Integer n = (Integer) numcalls.get();
if (n == null) n = new Integer(1);
else n = new Integer(n.intValue() + 1);
numcalls.set(n);
System.out.println(Thread.currentThread().getName() + ": " + n);
for(int i = 0, j=0; i < 1000000; i++) j += i;
try {
System.out.println("Current Thread Executing "+Thread.currentThread());
//Thread.sleep(2000);
//}
//catch (InterruptedException e) {}
Thread.yield();
}
}
As thread1.join() is called so it means that when control reaches to this line.thread1 must end its job first.
but this is not happening in output why ?Please Explain ?
Hi Steve I hope that now you could find the code formatted please go through It and Expalin ?
