How to run a class file from dir above or under it

[Andrew Luo]

Here is the A.java in test\woo\com\src dir

import java.util.Properties;

public class A {
public static void main(String[] args)
{
Properties p = System.getProperties();
p.setProperty("sdsd sdfs", "dsfs sdfs");
p.list(System.out);
}

}

javac ..\A.java

is used to compile it from the test\woo\com\src\classes dir. The A.class is in the test\woo\com\src as expected.
It seems no matter how do I use the -cp the in java command line from test\woo\com\src\classes, it always throws NoClassDefFoundError. Would anyone shed some light on this? Thanks!

[Hemnathbabu Kottaiveedu]

I am able to execute the above referenced program from a directory under it as well from a directory above it. I think there might be some syntax error on the command line when you are trying at your end. Following are the commands which I executed.

java -cp ..\ A (This is from the test\woo\com\src\classes dir)

java -cp src A (This is from the test\woo\com dir)

Following is a snippet of the output from the program

-- listing properties --
java.runtime.name=Java(TM) SE Runtime Environment
sun.boot.library.path=C:\Program Files\Java\jre6\bin
java.vm.version=19.1-b02
sdsd sdfs=dsfs sdfs
java.vm.vendor=Sun Microsystems Inc.
java.vendor.url=http://java.sun.com/
path.separator=;
java.vm.name=Java HotSpot(TM) Client VM
file.encoding.pkg=sun.io

Hope this helps !

Thanks,
Hemnath