int to byte[] gives BufferOverflowException

[Raghava Mutharaju]

I am trying to convert int to a byte array with the code below

int num = 2;
byte[] bytes = ByteBuffer.allocate(1).putInt(num).array();
for (byte b : bytes) {
    System.out.format("0x%x ", b);
}

I am getting a BufferOverflowException, if I allocate one byte for 2. Isn't it supposed to take only 1 byte? Unless I allocate 4 bytes, it gives the exception (even if I allocate 2 or 3 bytes). This might be something very simple and I might have asked a pretty silly question. But, what am I missing here?

[Ralph Cook]

From the javadoc for ByteBuffer.putInt(int value):

Writes four bytes containing the given int value, in the current byte order, into this buffer at the current position, and then increments the position by four.

rc

[Raghava Mutharaju]

Ok, I got it now. Thank you for pointing it out

Regards,
Raghava.