Explanation needed for this program

[Arvind Kurmi]

public class Demo1{
	public static void main (String[] args){
		int value;
		value =16;
		System.out.println("16 decimal = " + value);
		value = 020;
		System.out.println("20 octal = "+ value + "in decimal");
		value = 0x10;
		System.out.println("10 hexadecimal = "+ value+ "in decimal");
	}
}

output is :
16 decimal =16
20 octal = 16 in decimal
10 hexadecimal = 16 in decimal

Why every times 16 is display? can any one explain me this?

[Adam Johansson]

I suspect Java decides you want to see the result in decimal.

Check out http://www.java-forums.org/java-lang/7211-how-convert-integer-hexadecimal-octal-number.html

EDIT:

If you're unsure what octal, decimal and hexadecimal means, check out:

http://mathworld.wolfram.com/Octal.html

[fred rosenberger]

Any numeric literal that starts with a "0" is considered to be written in Octal - or base 8. That means you can only use the digits from 0-7, and each position represents powers of 8.

Literals that begin with "0x" are considered Hexadecimal, which means you can use the digits 0-9 plus A-F. Each position represents a power of 16.

This sounds weird, but makes perfect sense for computers and representing things stored in computers.

[Jesper de Jong]

Arvind Kurmi wrote:Why every times 16 is display? can any one explain me this?

Did you expect something else? For example, did you expect that it would display "0x10" when you initialize the integer with 0x10?

Note that decimal, octal and hexadecimal are just different ways to represent numbers. But the number itself it just a number and nothing more: it does not have some property that says that the number is decimal, octal or hexadecimal. In other words, the variable doesn't know anything about how you wrote it in your source code.

[Arvind Kurmi]

Adam Johansson, fred rosenberger , Jesper de Jong.
thanks
it was really helpful