getMessage

[abhay jain]

class Excee
{

	public static void main(String args[])
	{

		int a[]= new int [5];

		try{
			a[6]=200;
		}
		catch(ArrayIndexOutOfBoundsException e){
		System.out.println(e.getMessage());
		}

	}


}

/*

output

6

this number always relevent to index number here a[6]

why ???


so far i know that ...
getMessage():

Returns the error message string of this throwable object.

Returns:
the error message string of this Throwable object if it was created with an error

message string; or null if it was created with no error message.

.. but still don't understand why ??? it shows that index 6 (in that case )


*/

[fred rosenberger]

because your array only has 5 elements. there is no a[6].

And since you know you have an ArrayIndexOutOfBoundsException, the only other thing you might need to know is what index you are trying to access.

What would you expect it to say?

[abhay jain]

fred rosenberger wrote:because your array only has 5 elements. there is no a[6].

And since you know you have an ArrayIndexOutOfBoundsException, the only other thing you might need to know is what index you are trying to access.

What would you expect it to say?

oh ! now i understand .. thanks

[Jesper de Jong]

Try changing line 13 to:

e.printStackTrace();

instead of just printing the information message of the exception.